What is the limit as x approaches 0+of x^{18x} ?

The limit as x approaches 0+of x^{18x} is 1

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limit as x approaches 0+of x^{18x}

x \to 0 + lim (x^{18 x})

1

Solution steps

x \to 0 + lim (x^{18 x})

Apply exponent rules

= x \to 0 + lim (e^{18 x l n (x)})

Apply the Limit Chain Rule:

1

= 1

x \to 0 lim (e^{- x} - 1)

h \to 0 lim (\frac{( 1 + h ) ^{3 π} - 1}{h})

x \to - \infty lim (- 17 x^{2})

x \to 100 lim (x)

x \to - 4 lim (x^{2} - 10)

What is the limit as x approaches 0+of x^{18x} ?
The limit as x approaches 0+of x^{18x} is 1