What is the integral of tan(θ)sec(θ)sec^2(θ) ?

The integral of tan(θ)sec(θ)sec^2(θ) is (sec^3(θ))/3+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of tan(θ)sec(θ)sec^2(θ)

\int tan (θ) sec (θ) sec^{2} (θ) d θ

\frac{sec ^{3} ( θ )}{3} + C

Solution steps

\int tan (θ) sec (θ) sec^{2} (θ) d θ

Apply u-substitution

: \int u^{2} d u

= \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{u ^{3}}{3}

Substitute back

u = sec (θ)

= \frac{sec ^{3} ( θ )}{3}

Add a constant to the solution

= \frac{sec ^{3} ( θ )}{3} + C

\frac{d}{d x} (ln (4 + ln (x)))

\frac{\partial}{\partial x} (a x ln (a x))

\int 49 y d y

e^{- 4 t}

\int \frac{x}{2 x ^{2} - 5} d x

What is the integral of tan(θ)sec(θ)sec^2(θ) ?
The integral of tan(θ)sec(θ)sec^2(θ) is (sec^3(θ))/3+C