What is the limit as x approaches 0 of 1/(x^2+3x) ?

The limit as x approaches 0 of 1/(x^2+3x) is diverges

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limit as x approaches 0 of 1/(x^2+3x)

x \to 0 lim (\frac{1}{x ^{2} + 3 x})

diverges

Solution steps

x \to 0 lim (\frac{1}{x ^{2} + 3 x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{x ^{2} + 3 x}) = \infty

x \to 0 - lim (\frac{1}{x ^{2} + 3 x}) = - \infty

= diverges

x \to 1 + lim ((8 x + \frac{2}{x})^{5})

x \to \infty lim (3^{2})

x \to - 7 + lim (\frac{x + 7}{∣ x + 7 ∣})

x \to 0 lim (x ln (x) - 1)

x \to 0 + lim (\frac{sin ( x )}{x})

What is the limit as x approaches 0 of 1/(x^2+3x) ?
The limit as x approaches 0 of 1/(x^2+3x) is diverges