What is (\partial)/(\partial y)(x^2+x/y) ?

The answer to (\partial)/(\partial y)(x^2+x/y) is -x/(y^2)

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(\partial)/(\partial y)(x^2+x/y)

\frac{\partial}{\partial y} (x^{2} + \frac{x}{y})

- \frac{x}{y ^{2}}

Solution steps

\frac{\partial}{\partial y} (x^{2} + \frac{x}{y})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (\frac{x}{y})

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (\frac{x}{y}) = - \frac{x}{y ^{2}}

= 0 - \frac{x}{y ^{2}}

Simplify

= - \frac{x}{y ^{2}}

\int x^{11} x^{6} + 6 d x

2 x^{2} - 3 x + 4

x \to 1 lim (\frac{x - 2}{x - 1})

x \to 0 + lim (ln (x) tan (x))

x \to - 4 lim (\frac{2}{( x + 4 ) ^{6}})

What is (\partial)/(\partial y)(x^2+x/y) ?
The answer to (\partial)/(\partial y)(x^2+x/y) is -x/(y^2)