What is the limit as x approaches-1 of 2/((x+1)^2) ?

The limit as x approaches-1 of 2/((x+1)^2) is infinity

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limit as x approaches-1 of 2/((x+1)^2)

x \to - 1 lim (\frac{2}{( x + 1 ) ^{2}})

\infty

Solution steps

x \to - 1 lim (\frac{2}{( x + 1 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 1 - lim (\frac{2}{( x + 1 ) ^{2}}) = \infty

x \to - 1 + lim (\frac{2}{( x + 1 ) ^{2}}) = \infty

= \infty

x \to 0 lim (arctan (1))

x \to - 2 lim (\frac{x}{4 - x ^{2}})

x \to 0 lim (\frac{1}{x} - 2 csc (x))

θ \to 0 lim (sin (3 θ))

x \to \infty lim (\frac{1 - cos ( 4 x )}{x ^{2}})

What is the limit as x approaches-1 of 2/((x+1)^2) ?
The limit as x approaches-1 of 2/((x+1)^2) is infinity