What is the limit as x approaches 0 of cos(x+1+6^x) ?

The limit as x approaches 0 of cos(x+1+6^x) is cos(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of cos(x+1+6^x)

x \to 0 lim (cos (x + 1 + 6^{x}))

cos (2)

Decimal

- 0.41614 \dots

Solution steps

x \to 0 lim (cos (x + 1 + 6^{x}))

Plug in the value

x = 0

= cos (0 + 1 + 6^{0})

Simplify

= cos (2)

n \to \infty lim (2 - \frac{1}{n})

x \to 0 + lim (x cos (\frac{π}{x}))

x \to \infty lim (\frac{1. 1 ^{x}}{x})

x \to 4 lim (\frac{1}{2 x})

x \to \frac{4}{5} lim (\frac{1}{5 x - 4})

What is the limit as x approaches 0 of cos(x+1+6^x) ?
The limit as x approaches 0 of cos(x+1+6^x) is cos(2)