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Popular >

x^2y^'+y^2=xy

Solution

x^{2} y^{^{'}} + y^{2} = x y

Solution

y = \frac{x}{ln ( x ) + c _{1}}

Solution steps

x^{2} y^{'} (x) + y^{2} = x y

Solve Bernoulli ODE:

y = \frac{x}{ln ( x ) + c _{1}}

y = \frac{x}{ln ( x ) + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for x^2y^'+y^2=xy ?
The solution for x^2y^'+y^2=xy is y= x/(ln(x)+c_{1)}