What is the limit as θ approaches 0 of (1-sin^2(θ))^{1/2} ?

The limit as θ approaches 0 of (1-sin^2(θ))^{1/2} is 1

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limit as θ approaches 0 of (1-sin^2(θ))^{1/2}

θ \to 0 lim ((1 - sin^{2} (θ))^{\frac{1}{2}})

1

Solution steps

θ \to 0 lim ((1 - sin^{2} (θ))^{\frac{1}{2}})

Plug in the value

θ = 0

= (1 - sin^{2} (0))^{\frac{1}{2}}

Simplify

(1 - sin^{2} (0))^{\frac{1}{2}} : 1

= 1

x \to 0 lim (x cos (\frac{15}{x}))

x \to - \infty lim (1 - (x^{2} - 2 x + 2) e^{- x})

x \to - \frac{π}{2} lim (- 3 x - \frac{π}{2})

x \to - 1 lim (\frac{x + 5}{x ^{2} - 1})

x \to 2 lim (arcsin (\frac{x}{2}))

What is the limit as θ approaches 0 of (1-sin^2(θ))^{1/2} ?
The limit as θ approaches 0 of (1-sin^2(θ))^{1/2} is 1