What is the integral of (x^2)^2x^2)^2 ?

The integral of (x^2)^2x^2)^2 is (x^{32})/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^2)^2x^2)^2

\int (((x^{2})^{2})^{2})^{2} d (((x^{2})^{2})^{2})^{2}

\frac{x ^{32}}{2} + C

Solution steps

\int (((x^{2})^{2})^{2})^{2} d (((x^{2})^{2})^{2})^{2}

Apply the Power Rule

: \frac{x ^{32}}{2}

= \frac{x ^{32}}{2}

Add a constant to the solution

= \frac{x ^{32}}{2} + C

arctan (e^{x})

\frac{d x}{d t} = \frac{5}{x e ^{t + 6 x}}

\int \frac{t}{2} d t

\frac{d}{d x} (x^{2} + 2 x + 1)

\int_{1}^{2} \int_{2}^{4} x y^{3} (e^{2})^{x^{2} y^{2}} d x d y

What is the integral of (x^2)^2x^2)^2 ?
The integral of (x^2)^2x^2)^2 is (x^{32})/2+C