What is the limit as x approaches 3 of (x^2-6x-9)/(x-3) ?

The limit as x approaches 3 of (x^2-6x-9)/(x-3) is diverges

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limit as x approaches 3 of (x^2-6x-9)/(x-3)

x \to 3 lim (\frac{x ^{2} - 6 x - 9}{x - 3})

diverges

Solution steps

x \to 3 lim (\frac{x ^{2} - 6 x - 9}{x - 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x ^{2} - 6 x - 9}{x - 3}) = - \infty

x \to 3 - lim (\frac{x ^{2} - 6 x - 9}{x - 3}) = \infty

= diverges

x \to - 8 lim (\frac{1}{x + 8})

x \to 0 lim (\frac{3 x}{e ^{4 x}})

x \to 0 lim (- \frac{∣ x ∣}{x})

x \to 1 lim (x^{3} - x^{2} - x + 1)

x \to 2 lim (x + 34)

What is the limit as x approaches 3 of (x^2-6x-9)/(x-3) ?
The limit as x approaches 3 of (x^2-6x-9)/(x-3) is diverges