What is the limit as x approaches 0 of ln(1+2x^2) ?

The limit as x approaches 0 of ln(1+2x^2) is 0

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limit as x approaches 0 of ln(1+2x^2)

x \to 0 lim (ln (1 + 2 x^{2}))

0

Solution steps

x \to 0 lim (ln (1 + 2 x^{2}))

Plug in the value

x = 0

= ln (1 + 2 \cdot 0^{2})

Simplify

ln (1 + 2 \cdot 0^{2}) : 0

= 0

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What is the limit as x approaches 0 of ln(1+2x^2) ?
The limit as x approaches 0 of ln(1+2x^2) is 0