What is the limit as x approaches pi/2+of cot(x) ?

The limit as x approaches pi/2+of cot(x) is 0

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limit as x approaches pi/2+of cot(x)

x \to \frac{π}{2} + lim (cot (x))

0

Solution steps

x \to \frac{π}{2} + lim (cot (x))

Plug in the value

x = \frac{π}{2}

= cot (\frac{π}{2})

Use the following trivial identity:

cot (\frac{π}{2}) = 0

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

= 0

x \to \infty lim ((1 - (\frac{1}{x}))^{2 x})

x \to 0 lim (\frac{3 x - sin ( k x )}{x})

x \to \frac{π}{2} lim (3 tan (x))

x \to \infty lim (0.6 5^{x})

x \to 4 - lim (\frac{1}{x + 4})

What is the limit as x approaches pi/2+of cot(x) ?
The limit as x approaches pi/2+of cot(x) is 0