What is the derivative of f(x)=4x^3-1x-2 ?

The derivative of f(x)=4x^3-1x-2 is 12x^2-1

What is the first derivative of f(x)=4x^3-1x-2 ?

The first derivative of f(x)=4x^3-1x-2 is 12x^2-1

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derivative of

f (x) = 4 x^{3} - 1 x - 2

12 x^{2} - 1

Solution steps

\frac{d}{d x} (4 x^{3} - 1 \cdot x - 2)

Simplify

4 x^{3} - 1 \cdot x - 2 : 4 x^{3} - x - 2

= \frac{d}{d x} (4 x^{3} - x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d x}{d x} - \frac{d}{d x} (2)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 12 x^{2} - 1 - 0

Simplify

= 12 x^{2} - 1

\int_{0}^{2} \frac{1}{( x - 1 ) ^{\frac{2}{5}}} d x

\int_{6}^{13} \frac{1}{( x - 8 ) ^{2}} d x

x y^{^{'}} - y = \frac{3}{4} x ln (x)

\frac{\partial}{\partial y} (2 x y)

\frac{d y}{d x}, x y = 24

What is the derivative of f(x)=4x^3-1x-2 ?
The derivative of f(x)=4x^3-1x-2 is 12x^2-1
What is the first derivative of f(x)=4x^3-1x-2 ?
The first derivative of f(x)=4x^3-1x-2 is 12x^2-1