What is the limit as x approaches 0+of x^{-1} ?

The limit as x approaches 0+of x^{-1} is infinity

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limit as x approaches 0+of x^{-1}

x \to 0 + lim (x^{- 1})

\infty

Solution steps

x \to 0 + lim (x^{- 1})

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= x \to 0 + lim (\frac{1}{x})

For

x

approaching

0

from the right

, x > 0 \Rightarrow x > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

x \to \infty lim (x^{5} e^{- 2 x})

x \to 2 - lim (\frac{4}{x - 2})

x \to - 3 lim (\frac{x + 3}{x})

x \to 2 lim (6 x + 7)

x \to 1 lim ((2 x - 1)^{2} - 2)

What is the limit as x approaches 0+of x^{-1} ?
The limit as x approaches 0+of x^{-1} is infinity