What is the integral from 0 to infinity of 1/x ?

The integral from 0 to infinity of 1/x is diverges

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integral from 0 to infinity of 1/x

\int_{0}^{\infty} \frac{1}{x} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{x} d x

Compute the indefinite integral:

\int \frac{1}{x} d x = ln ∣ x ∣ + C

Compute the boundaries:

\int_{0}^{\infty} \frac{1}{x} d x =

diverges

= diverges

x + e^{2 x}

(0, 0), (5, 1)

(2 x - 5)^{4} (x^{2} + x + 1)^{5}

\int (1 - sin (x))^{\frac{1}{2}} d x

\frac{d}{d x} (ln (2 x))

What is the integral from 0 to infinity of 1/x ?
The integral from 0 to infinity of 1/x is diverges