What is the limit as x approaches 0 of 2x^4-x^2-8x ?

The limit as x approaches 0 of 2x^4-x^2-8x is 0

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limit as x approaches 0 of 2x^4-x^2-8x

x \to 0 lim (2 x^{4} - x^{2} - 8 x)

0

Solution steps

x \to 0 lim (2 x^{4} - x^{2} - 8 x)

Plug in the value

x = 0

= 2 \cdot 0^{4} - 0^{2} - 8 \cdot 0

Simplify

= 0

x \to 0 - lim (\frac{1}{1 - x})

x \to 1 lim (5 x + 8)

x \to 3 + lim (\frac{1}{( x - 3 )})

x \to 1 lim (5 x - 1)

x \to 3 lim (x^{2} + 2 x - 4)

What is the limit as x approaches 0 of 2x^4-x^2-8x ?
The limit as x approaches 0 of 2x^4-x^2-8x is 0