What is the limit as x approaches-1 of (x+5)/(x+1) ?

The limit as x approaches-1 of (x+5)/(x+1) is diverges

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limit as x approaches-1 of (x+5)/(x+1)

x \to - 1 lim (\frac{x + 5}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{x + 5}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x + 5}{x + 1}) = \infty

x \to - 1 - lim (\frac{x + 5}{x + 1}) = - \infty

= diverges

x \to 0 lim (4 x + 1)

x \to 0 lim (x + (\frac{1}{x}))

x \to 9 lim (\frac{1}{x - 3})

x \to 0 lim (sin (x) csc (6 x))

x \to 1 - lim (2 e^{x - 1})

What is the limit as x approaches-1 of (x+5)/(x+1) ?
The limit as x approaches-1 of (x+5)/(x+1) is diverges