What is the derivative of-10x+3cos(x) ?

The derivative of-10x+3cos(x) is -10-3sin(x)

What is the first derivative of-10x+3cos(x) ?

The first derivative of-10x+3cos(x) is -10-3sin(x)

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\frac{d}{d x} (- 10 x + 3 cos (x))

- 10 - 3 sin (x)

Solution steps

\frac{d}{d x} (- 10 x + 3 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (10 x) + \frac{d}{d x} (3 cos (x))

\frac{d}{d x} (10 x) = 10

\frac{d}{d x} (3 cos (x)) = - 3 sin (x)

= - 10 - 3 sin (x)

\frac{d ^{2}}{d x ^{2}} ((2 x + 5)^{7})

\int_{1}^{4} (\frac{4}{x} - \frac{16}{x ^{2}}) d x

\frac{\partial}{\partial x} (\frac{3 x + 9}{2 - x})

\frac{d}{d x} (\frac{6 x}{x + 5})

What is the derivative of-10x+3cos(x) ?
The derivative of-10x+3cos(x) is -10-3sin(x)
What is the first derivative of-10x+3cos(x) ?
The first derivative of-10x+3cos(x) is -10-3sin(x)