What is the integral of e^{-5x}cos(3x) ?

The integral of e^{-5x}cos(3x) is (3e^{-5x}sin(3x))/(34)-(5e^{-5x}cos(3x))/(34)+C

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integral of e^{-5x}cos(3x)

\int e^{- 5 x} cos (3 x) d x

\frac{3 e ^{- 5 x} sin ( 3 x )}{34} - \frac{5 e ^{- 5 x} cos ( 3 x )}{34} + C

Solution steps

\int e^{- 5 x} cos (3 x) d x

Apply Integration By Parts

: \frac{1}{3} e^{- 5 x} sin (3 x) - \int - \frac{5}{3} e^{- 5 x} sin (3 x) d x

= \frac{1}{3} e^{- 5 x} sin (3 x) - \int - \frac{5}{3} e^{- 5 x} sin (3 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} e^{- 5 x} sin (3 x) - (- \frac{5}{3} \cdot \int e^{- 5 x} sin (3 x) d x)

Apply Integration By Parts

: - \frac{1}{3} e^{- 5 x} cos (3 x) - \int \frac{5}{3} e^{- 5 x} cos (3 x) d x

= \frac{1}{3} e^{- 5 x} sin (3 x) - (- \frac{5}{3} (- \frac{1}{3} e^{- 5 x} cos (3 x) - \int \frac{5}{3} e^{- 5 x} cos (3 x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} e^{- 5 x} sin (3 x) - (- \frac{5}{3} (- \frac{1}{3} e^{- 5 x} cos (3 x) - \frac{5}{3} \cdot \int e^{- 5 x} cos (3 x) d x))

Therefore

\int e^{- 5 x} cos (3 x) d x = \frac{1}{3} e^{- 5 x} sin (3 x) - (- \frac{5}{3} (- \frac{1}{3} e^{- 5 x} cos (3 x) - \frac{5}{3} \cdot \int e^{- 5 x} cos (3 x) d x))

Isolate

\int e^{- 5 x} cos (3 x) d x

= \frac{3 e ^{- 5 x} sin ( 3 x )}{34} - \frac{5 e ^{- 5 x} cos ( 3 x )}{34}

Add a constant to the solution

= \frac{3 e ^{- 5 x} sin ( 3 x )}{34} - \frac{5 e ^{- 5 x} cos ( 3 x )}{34} + C

\frac{5}{2} + \frac{3}{2} x

\frac{d}{d x} (\frac{1}{( x - 7 ) ^{2}})

\int \frac{cos ( ln ( x ) )}{3 x} d x

f (x) = tan (4) x^{3}

y = (x)^{5 x}

What is the integral of e^{-5x}cos(3x) ?
The integral of e^{-5x}cos(3x) is (3e^{-5x}sin(3x))/(34)-(5e^{-5x}cos(3x))/(34)+C