What is the f(x)=(x^2-3x+8)^3 ?

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f(x)=(x^2-3x+8)^3

f (x) = (x^{2} - 3 x + 8)^{3}

Domain : - \infty < x < \infty

Range : f (x) \geq \frac{12167}{64}

Y Intercepts : (0, 512)

Asymptotes : None

Extreme Points : Minimum (\frac{3}{2}, \frac{12167}{64})

Interval Notation

Domain : (- \infty, \infty)

Range : [\frac{12167}{64}, \infty)

Solution steps

Domain of

(x^{2} - 3 x + 8)^{3} : - \infty < x < \infty

Range of

(x^{2} - 3 x + 8)^{3} : f (x) \geq \frac{12167}{64}

Axis interception points of

(x^{2} - 3 x + 8)^{3} :

Y Intercepts

: (0, 512)

Asymptotes of

(x^{2} - 3 x + 8)^{3} :

None

Extreme Points of

(x^{2} - 3 x + 8)^{3} :

Minimum

(\frac{3}{2}, \frac{12167}{64})

x \to - \infty lim (x^{2} + 1)

y^{^{''}} - 2 y^{^{'}} - 3 y = - 5 x e^{4 x}

f (x) = \frac{3}{x + 5}