What is the limit as x approaches 0 of 1/(1+e^{-x)} ?

The limit as x approaches 0 of 1/(1+e^{-x)} is 1/2

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limit as x approaches 0 of 1/(1+e^{-x)}

x \to 0 lim (\frac{1}{1 + e ^{- x}})

\frac{1}{2}

Decimal Notation

0.5

Solution steps

x \to 0 lim (\frac{1}{1 + e ^{- x}})

Plug in the value

x = 0

= \frac{1}{1 + e ^{- 0}}

Simplify

= \frac{1}{2}

n \to 0 + lim (n^{2} ln (4 n^{2}))

x \to 2 π lim (2 x cos (x))

x \to 0 lim (175)

x \to 0 + lim (\frac{1}{- 2 x})

x \to 1 lim (x^{2} + x + 2)

What is the limit as x approaches 0 of 1/(1+e^{-x)} ?
The limit as x approaches 0 of 1/(1+e^{-x)} is 1/2