What is the limit as x approaches-1 of-1/(x+1) ?

The limit as x approaches-1 of-1/(x+1) is diverges

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limit as x approaches-1 of-1/(x+1)

x \to - 1 lim (- \frac{1}{x + 1})

diverges

Solution steps

x \to - 1 lim (- \frac{1}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (- \frac{1}{x + 1}) = - \infty

x \to - 1 - lim (- \frac{1}{x + 1}) = \infty

= diverges

x \to 3 lim (\frac{3 x - 1}{x + 1})

x \to - 2 lim (x - 1)

x \to 0 lim (3 x + 7)

x \to 1 lim (11)

u \to 1 lim (\frac{u ^{2} - 1}{u - 1})

What is the limit as x approaches-1 of-1/(x+1) ?
The limit as x approaches-1 of-1/(x+1) is diverges