What is the limit as x approaches 0 of (7x+5x^2)/x ?

The limit as x approaches 0 of (7x+5x^2)/x is 7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (7x+5x^2)/x

x \to 0 lim (\frac{7 x + 5 x ^{2}}{x})

7

Solution steps

x \to 0 lim (\frac{7 x + 5 x ^{2}}{x})

Simplify

\frac{7 x + 5 x ^{2}}{x} : 7 + 5 x

= x \to 0 lim (7 + 5 x)

Plug in the value

x = 0

= 7 + 5 \cdot 0

Simplify

= 7

x \to 0 + lim (\frac{( x - 3 )}{x ^{2}})

x \to \frac{1}{2} lim (2 x - 1)

x \to - 4 lim ((3 x + 2) (x - 2))

x \to 4 lim (2 x^{2} + 4 x + 1)

x \to 0 lim (ln (1 - e^{x}))

What is the limit as x approaches 0 of (7x+5x^2)/x ?
The limit as x approaches 0 of (7x+5x^2)/x is 7