What is inverse oflaplace (sqrt(2))/(s^5) ?

The answer to inverse oflaplace (sqrt(2))/(s^5) is (t^4)/(12sqrt(2))

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inverse oflaplace (sqrt(2))/(s^5)

inverse laplace

\frac{2}{s ^{5}}

\frac{t ^{4}}{12 2}

Solution steps

L^{- 1} {\frac{2}{s ^{5}}}

= L^{- 1} {\frac{1}{12 2} \cdot \frac{24}{s ^{5}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{12 2} L^{- 1} {\frac{24}{s ^{5}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{24}{s ^{5}}} = t^{4}

= \frac{1}{12 2} t^{4}

= \frac{t ^{4}}{12 2}

x \to 0 lim (\frac{( 2 + x ) ^{3} - 8}{x})

\int - 4 sin (4 x) d x

\frac{d}{d x} (cos (e^{- x}))

\int \frac{1}{( x ^{2} + y ^{2} )} d y

x^{0.5}

What is inverse oflaplace (sqrt(2))/(s^5) ?
The answer to inverse oflaplace (sqrt(2))/(s^5) is (t^4)/(12sqrt(2))