What is the limit as x approaches 0 of 1-(ln(x^2))/x ?

The limit as x approaches 0 of 1-(ln(x^2))/x is diverges

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limit as x approaches 0 of 1-(ln(x^2))/x

x \to 0 lim (1 - \frac{ln ( x ^{2} )}{x})

diverges

Solution steps

x \to 0 lim (1 - \frac{ln ( x ^{2} )}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (1 - \frac{ln ( x ^{2} )}{x}) = \infty

x \to 0 - lim (1 - \frac{ln ( x ^{2} )}{x}) = 1 +

Does not exist

\cdot \infty

= diverges

x \to 2 lim (4 x + 8)

x \to - 2 lim (\frac{1}{x - 1})

x \to 0 lim (- \frac{ln ( 1 - x )}{x})

x \to 1 + lim (ln (x^{x}))

(x) \to (0) lim (\frac{x}{x ^{2}})

What is the limit as x approaches 0 of 1-(ln(x^2))/x ?
The limit as x approaches 0 of 1-(ln(x^2))/x is diverges