What is the limit as x approaches 0 of sqrt(x)ln(2x) ?

The limit as x approaches 0 of sqrt(x)ln(2x) is Does not exist

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limit as x approaches 0 of sqrt(x)ln(2x)

x \to 0 lim (x ln (2 x))

Does not exist

Solution steps

x \to 0 lim (x ln (2 x))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x ln (2 x)) = 0

x \to 0 - lim (x ln (2 x)) =

Does not exist

= Does not exist

x \to 0 lim (\frac{x}{ln ( 2 x + 1 )})

x \to \infty lim ((1 + \frac{0.02}{x})^{2 x})

x \to 0 lim (3 x^{2} + 2)

x \to \infty lim ((\frac{2 x + 1}{x + 3})^{\frac{3 x + 2}{x - 5}})

x \to 0 lim (\frac{sin ( x )}{arcsin ( x )})

What is the limit as x approaches 0 of sqrt(x)ln(2x) ?
The limit as x approaches 0 of sqrt(x)ln(2x) is Does not exist