What is the derivative of 9e^x(cos(x-sin(x))) ?

The derivative of 9e^x(cos(x-sin(x))) is -18e^xsin(x)

What is the first derivative of 9e^x(cos(x-sin(x))) ?

The first derivative of 9e^x(cos(x-sin(x))) is -18e^xsin(x)

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\frac{d}{d x} (9 e^{x} (cos (x) - sin (x)))

- 18 e^{x} sin (x)

Solution steps

\frac{d}{d x} (9 e^{x} (cos (x) - sin (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{x} (cos (x) - sin (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (x) - sin (x)

= 9 (\frac{d}{d x} (e^{x}) (cos (x) - sin (x)) + \frac{d}{d x} (cos (x) - sin (x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x) - sin (x)) = - sin (x) - cos (x)

= 9 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x})

Simplify

9 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x}) : - 18 e^{x} sin (x)

= - 18 e^{x} sin (x)

x \to 0 lim ((1 + 6 x)^{\frac{7}{x}})

2 x - tan (x)

k = 1 \sum \infty \frac{1}{k + 6}

f (x) = \frac{3 x}{4 - x ^{2}}, at x = 1

x \to 3 lim (\frac{x ^{2} + 9}{x - 3})

What is the derivative of 9e^x(cos(x-sin(x))) ?
The derivative of 9e^x(cos(x-sin(x))) is -18e^xsin(x)
What is the first derivative of 9e^x(cos(x-sin(x))) ?
The first derivative of 9e^x(cos(x-sin(x))) is -18e^xsin(x)