What is the limit as x approaches 3 of (x^2+9)/(x-3) ?

The limit as x approaches 3 of (x^2+9)/(x-3) is diverges

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limit as x approaches 3 of (x^2+9)/(x-3)

x \to 3 lim (\frac{x ^{2} + 9}{x - 3})

diverges

Solution steps

x \to 3 lim (\frac{x ^{2} + 9}{x - 3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{x ^{2} + 9}{x - 3}) = \infty

x \to 3 - lim (\frac{x ^{2} + 9}{x - 3}) = - \infty

= diverges

x \to 7 + lim (x + 2)

\frac{\partial}{\partial x} (2 x^{\frac{2}{3}} y^{\frac{1}{3}})

n = 0 \sum \infty (- 1)^{n}

\int (cos (x) + 5^{x}) d x

\int (3^{x}) d x

What is the limit as x approaches 3 of (x^2+9)/(x-3) ?
The limit as x approaches 3 of (x^2+9)/(x-3) is diverges