What is the limit as x approaches 2 of (x^2-9)/(x+3) ?

The limit as x approaches 2 of (x^2-9)/(x+3) is -1

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limit as x approaches 2 of (x^2-9)/(x+3)

x \to 2 lim (\frac{x ^{2} - 9}{x + 3})

- 1

Solution steps

x \to 2 lim (\frac{x ^{2} - 9}{x + 3})

Plug in the value

x = 2

= \frac{2 ^{2} - 9}{2 + 3}

Simplify

\frac{2 ^{2} - 9}{2 + 3} : - 1

= - 1

x \to 0 lim (\frac{2 x + sin ( x )}{x})

x \to - 1 lim (- 4 x)

x \to - \infty lim (3 x + 2)

x \to 0 + lim (x^{\frac{x}{3}})

x \to 0 lim (\frac{6 x}{cot ( x )})

What is the limit as x approaches 2 of (x^2-9)/(x+3) ?
The limit as x approaches 2 of (x^2-9)/(x+3) is -1