What is the limit as x approaches 0-of 6(1/x-cot(x)) ?

The limit as x approaches 0-of 6(1/x-cot(x)) is 0

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limit as x approaches 0-of 6(1/x-cot(x))

x \to 0 - lim (6 (\frac{1}{x} - cot (x)))

0

Solution steps

x \to 0 - lim (6 (\frac{1}{x} - cot (x)))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 6 \cdot x \to 0 - lim (\frac{1}{x} - cot (x))

Multiply by the conjugate of

\frac{1}{x} - cot (x) : \frac{\frac{1}{x ^{2}} - cot ^{2} ( x )}{\frac{1}{x} + cot ( x )}

= 6 \cdot x \to 0 - lim (\frac{\frac{1}{x ^{2}} - cot ^{2} ( x )}{\frac{1}{x} + cot ( x )})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= 6 \cdot \frac{lim _{x \to 0 -} ( \frac{1}{x ^{2}} - cot ^{2} ( x ) )}{lim _{x \to 0 -} ( \frac{1}{x} + cot ( x ) )}

x \to 0 - lim (\frac{1}{x ^{2}} - cot^{2} (x)) = \frac{2}{3}

x \to 0 - lim (\frac{1}{x} + cot (x)) = - \infty

= 6 \cdot \frac{\frac{2}{3}}{- \infty}

Simplify

6 \cdot \frac{\frac{2}{3}}{- \infty} : 0

= 0

x \to 0 lim (x (ln (4) x + 2) \cdot 4^{x - 3})

x \to \infty lim (- e^{- x} - 1)

h \to 0 lim (\frac{( a + h ) ^{\frac{2}{3}} - a ^{\frac{2}{3}}}{h})

x \to 2 + lim (2 x^{2} + \frac{a}{2} x - 4)

x \to 5 lim (\frac{x ^{2} - 4}{x - 2})

What is the limit as x approaches 0-of 6(1/x-cot(x)) ?
The limit as x approaches 0-of 6(1/x-cot(x)) is 0