What is the limit as x approaches 0 of (1+|x|)^{1/x} ?

The limit as x approaches 0 of (1+|x|)^{1/x} is diverges

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limit as x approaches 0 of (1+|x|)^{1/x}

x \to 0 lim ((1 + ∣ x ∣)^{\frac{1}{x}})

diverges

Solution steps

x \to 0 lim ((1 + ∣ x ∣)^{\frac{1}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((1 + ∣ x ∣)^{\frac{1}{x}}) = e

x \to 0 - lim ((1 + ∣ x ∣)^{\frac{1}{x}}) = \frac{1}{e}

= diverges

x \to 1 lim (3 x + 4)

x \to 0 lim ((sin (x)) ln (x))

x \to 0 lim (\frac{2 x}{x ^{2} + 4})

x \to - \infty lim (2 - x^{4})

x \to \frac{64}{37} lim ([\frac{x}{5}])

What is the limit as x approaches 0 of (1+|x|)^{1/x} ?
The limit as x approaches 0 of (1+|x|)^{1/x} is diverges