What is the derivative of x^4+1/(32x^2) ?

The derivative of x^4+1/(32x^2) is 4x^3-1/(16x^3)

What is the first derivative of x^4+1/(32x^2) ?

The first derivative of x^4+1/(32x^2) is 4x^3-1/(16x^3)

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\frac{d}{d x} (x^{4} + \frac{1}{32 x ^{2}})

4 x^{3} - \frac{1}{16 x ^{3}}

Solution steps

\frac{d}{d x} (x^{4} + \frac{1}{32 x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (\frac{1}{32 x ^{2}})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (\frac{1}{32 x ^{2}}) = - \frac{1}{16 x ^{3}}

= 4 x^{3} - \frac{1}{16 x ^{3}}

\frac{\partial}{\partial x} (x^{0.5} \cdot y^{0.5})

\frac{d}{d x} (4 + 3 sin (x))

\int \frac{e ^{x} + e ^{- x}}{2} d x

x \to + 0 + lim (ln (0))

\int x^{3} \cdot sin (x) d x

What is the derivative of x^4+1/(32x^2) ?
The derivative of x^4+1/(32x^2) is 4x^3-1/(16x^3)
What is the first derivative of x^4+1/(32x^2) ?
The first derivative of x^4+1/(32x^2) is 4x^3-1/(16x^3)