What is the integral from 0 to 2 of xln(x) ?

The integral from 0 to 2 of xln(x) is 2ln(2)-1

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integral from 0 to 2 of xln(x)

\int_{0}^{2} x ln (x) d x

2 ln (2) - 1

Decimal Notation

0.38629 \dots

Solution steps

\int_{0}^{2} x ln (x) d x

Apply Integration By Parts

: [\frac{1}{2} x^{2} ln (x) - \int \frac{x}{2} d x]_{0}^{2}

= [\frac{1}{2} x^{2} ln (x) - \int \frac{x}{2} d x]_{0}^{2}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= [\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}]_{0}^{2}

Compute the boundaries:

2 ln (2) - 1

= 2 ln (2) - 1

f (x) = 1^{4}

\frac{d}{d x} (lo g_{e} (sin (x)))

x + 2 y = 9, x + 6 = y^{2}

\int sin^{5} (13 x) d x

\int_{0}^{1} π (x^{3} - 1)^{2} d x

What is the integral from 0 to 2 of xln(x) ?
The integral from 0 to 2 of xln(x) is 2ln(2)-1