What is the limit as x approaches+0 of sin(1/x) ?

The limit as x approaches+0 of sin(1/x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches+0 of sin(1/x)

x \to + 0 lim (sin (\frac{1}{x}))

diverges

Solution steps

x \to 0 lim (sin (\frac{1}{x}))

Apply Limit Divergence Criterion:

diverges

= diverges

x \to 0 + lim (\frac{x}{e ^{- \frac{2}{x}}})

x \to 1 lim (4 x^{2} - 13 x + 12)

x \to 0 lim (2 - 4 x + 7 x^{2})

h \to 0 lim (cot (h) - csc (h))

x \to 0 lim (x^{(x^{x})})

What is the limit as x approaches+0 of sin(1/x) ?
The limit as x approaches+0 of sin(1/x) is diverges