What is the limit as t approaches 0 of cos(4t)(cos(8t)) ?

The limit as t approaches 0 of cos(4t)(cos(8t)) is 1

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limit as t approaches 0 of cos(4t)(cos(8t))

t \to 0 lim (cos (4 t) (cos (8 t)))

1

Solution steps

t \to 0 lim (cos (4 t) cos (8 t))

Plug in the value

t = 0

= cos (4 \cdot 0) cos (8 \cdot 0)

Simplify

cos (4 \cdot 0) cos (8 \cdot 0) : 1

= 1

x \to 0 lim (\frac{2}{x + 1})

x \to (- 2) - lim (\frac{1}{x + 2})

x \to 3 + lim (x^{2} - 9 + 2)

h \to 0 lim (h + 1)

x \to - 2 lim (x^{4} - 3 x^{3} + x - 3)

What is the limit as t approaches 0 of cos(4t)(cos(8t)) ?
The limit as t approaches 0 of cos(4t)(cos(8t)) is 1