What is the solution for (dy)/(dx)=(3x^2)/(1-y) ?

The solution for (dy)/(dx)=(3x^2)/(1-y) is y=1-sqrt(-2x^3+1-c_{1)},y=sqrt(-2x^3+1-c_{1)}+1

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(dy)/(dx)=(3x^2)/(1-y)

\frac{d y}{d x} = \frac{3 x ^{2}}{1 - y}

y = 1 - - 2 x^{3} + 1 - c_{1}, y = - 2 x^{3} + 1 - c_{1} + 1

Solution steps

\frac{d y}{d x} = \frac{3 x ^{2}}{1 - y}

Solve separable ODE:

y = 1 - - 2 x^{3} + 1 - c_{1}, y = - 2 x^{3} + 1 - c_{1} + 1

y = 1 - - 2 x^{3} + 1 - c_{1}, y = - 2 x^{3} + 1 - c_{1} + 1

x^{2} e^{- 5 x}

\int_{\frac{1}{3}}^{5} 6 x ln (3 x) d x

x^{2} \frac{d y}{d x} = y - x y, y (- 1) = - 1

ln (x), at 1

\frac{d}{d x} ((4 x + 1) (1 - x)^{3})

What is the solution for (dy)/(dx)=(3x^2)/(1-y) ?
The solution for (dy)/(dx)=(3x^2)/(1-y) is y=1-sqrt(-2x^3+1-c_{1)},y=sqrt(-2x^3+1-c_{1)}+1