What is the integral of (xsqrt(x))/(x^2) ?

The integral of (xsqrt(x))/(x^2) is 2sqrt(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (xsqrt(x))/(x^2)

\int \frac{x x}{x ^{2}} d x

2 x + C

Solution steps

\int \frac{x x}{x ^{2}} d x

Simplify

\frac{x x}{x ^{2}} : \frac{1}{x}

= \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 2 x^{\frac{1}{2}}

Apply radical rule:

= 2 x

Add a constant to the solution

= 2 x + C

x \to \infty lim (\frac{π}{3})

\int \frac{1}{( x ^{2} + x + 1 ) ^{2}} d x

\int_{0}^{4} ∣ x - 2 ∣ d x

\int \frac{1}{2 x ^{2} + 9 x + 4} d x

y = x, y = 0, x = 0, x = 7

What is the integral of (xsqrt(x))/(x^2) ?
The integral of (xsqrt(x))/(x^2) is 2sqrt(x)+C