What is the limit as h approaches 0 of (-1)/h ?

The limit as h approaches 0 of (-1)/h is diverges

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limit as h approaches 0 of (-1)/h

h \to 0 lim (\frac{- 1}{h})

diverges

Solution steps

h \to 0 lim (\frac{- 1}{h})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

h \to 0 + lim (\frac{- 1}{h}) = - \infty

h \to 0 - lim (\frac{- 1}{h}) = \infty

= diverges

x \to 2 lim (\frac{4 x + 7}{2 x + 1})

x \to 1 lim (I n (x))

x \to 1 lim (\frac{1}{1 + e ^{\frac{1}{x}}})

x \to 1 lim ((x - 1) \cdot ln (x - 1))

x \to - 1 lim (cos (2 π x - π))

What is the limit as h approaches 0 of (-1)/h ?
The limit as h approaches 0 of (-1)/h is diverges