What is the tangent of 7x+cox(x) ?

The tangent of 7x+cox(x) is o=(7(1+ca_{1}^2))/((1-ca_{1)^2)^2}x-(14ca_{1}^3)/((-ca_{1)^2+1)^2}

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tangent of 7x+cox(x)

tangent of

7 x + co x (x)

o = \frac{7 ( 1 + c a _{1}^{2} )}{( 1 - c a _{1}^{2} ) ^{2}} x - \frac{14 c a _{1}^{3}}{( - c a _{1}^{2} + 1 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{1}

Find the tangent point:

(a_{1}, \frac{7 a _{1}}{1 - c a _{1}^{2}})

Find the slope of

o = 7 x + co xx : \frac{d o}{d x} = \frac{7 ( 1 + c x ^{2} )}{( 1 - c x ^{2} ) ^{2}}

Compute the slope of

o = 7 x + co xx

x = a_{1} : m = \frac{7 ( 1 + c a _{1}^{2} )}{( 1 - c a _{1}^{2} ) ^{2}}

Find the line with slope m=

\frac{7 ( 1 + c a _{1}^{2} )}{( 1 - c a _{1}^{2} ) ^{2}}

and passing through

(a_{1}, \frac{7 a _{1}}{1 - c a _{1}^{2}}) : o = \frac{7 ( 1 + c a _{1}^{2} )}{( 1 - c a _{1}^{2} ) ^{2}} x - \frac{14 c a _{1}^{3}}{( - c a _{1}^{2} + 1 ) ^{2}}

o = \frac{7 ( 1 + c a _{1}^{2} )}{( 1 - c a _{1}^{2} ) ^{2}} x - \frac{14 c a _{1}^{3}}{( - c a _{1}^{2} + 1 ) ^{2}}

\frac{\partial}{\partial x} (e^{- x})

\int_{0}^{\frac{π}{8}} sin (2 x) d x

\int \frac{3}{2 - x} d x

\int_{1}^{3} 7 r^{3} ln (r) d r

\frac{4}{2 ( s - 3 ) ^{2} - 50}

What is the tangent of 7x+cox(x) ?
The tangent of 7x+cox(x) is o=(7(1+ca_{1}^2))/((1-ca_{1)^2)^2}x-(14ca_{1}^3)/((-ca_{1)^2+1)^2}