What is the limit as j approaches 0 of ((3-j)^2-9)/j ?

The limit as j approaches 0 of ((3-j)^2-9)/j is -6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as j approaches 0 of ((3-j)^2-9)/j

j \to 0 lim (\frac{( 3 - j ) ^{2} - 9}{j})

- 6

Solution steps

j \to 0 lim (\frac{( 3 - j ) ^{2} - 9}{j})

Simplify

\frac{( 3 - j ) ^{2} - 9}{j} : j - 6

= j \to 0 lim (j - 6)

Plug in the value

j = 0

= 0 - 6

Simplify

= - 6

x \to 0 lim (x (x - 2))

x \to 3.5 lim (\frac{( x - 2 )}{x})

x \to 0 lim ([x^{2} + 4 x + 4])

t \to 0 + lim (t ln ∣ t ∣)

x \to - \infty lim (5 x^{2})

What is the limit as j approaches 0 of ((3-j)^2-9)/j ?
The limit as j approaches 0 of ((3-j)^2-9)/j is -6