What is the limit as x approaches pi/2 of sin(x) ?

The limit as x approaches pi/2 of sin(x) is 1

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limit as x approaches pi/2 of sin(x)

x \to \frac{π}{2} lim (sin (x))

1

Solution steps

x \to \frac{π}{2} lim (sin (x))

Plug in the value

x = \frac{π}{2}

= sin (\frac{π}{2})

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

\int \frac{6}{x ^{2} + 10 x + 16} d x

\int 6 sin^{4} (x) d x

\frac{d}{d x} ((12 x^{2} - 12) (9 - 4 x))

\frac{\partial}{\partial x} (x^{2} - 2 x y + 3 y^{2} x^{3})

y = ln (\frac{x ^{2} - 1}{x ^{2} + 1})

What is the limit as x approaches pi/2 of sin(x) ?
The limit as x approaches pi/2 of sin(x) is 1