What is the limit as x approaches 0 of 1-e^{-1/x} ?

The limit as x approaches 0 of 1-e^{-1/x} is diverges

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limit as x approaches 0 of 1-e^{-1/x}

x \to 0 lim (1 - e^{- \frac{1}{x}})

diverges

Solution steps

x \to 0 lim (1 - e^{- \frac{1}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (1 - e^{- \frac{1}{x}}) = 1

x \to 0 - lim (1 - e^{- \frac{1}{x}}) = - \infty

= diverges

x \to \infty lim (x - 9)

x \to 5 lim (\frac{x ^{2} + 2}{3 x})

h \to 0 lim (2 h + 11)

x \to 0 lim (x^{s i n (7 x)})

x \to 0 lim (\frac{7 ^{x} - 3 ^{x}}{x})

What is the limit as x approaches 0 of 1-e^{-1/x} ?
The limit as x approaches 0 of 1-e^{-1/x} is diverges