What is the limit as n approaches infinity of e^0 ?

The limit as n approaches infinity of e^0 is 1

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limit as n approaches infinity of e^0

n \to \infty lim (e^{0})

1

Solution steps

n \to \infty lim (e^{0})

x \to a lim c = c

= e^{0}

Simplify

= 1

x \to 8 lim (- x^{2} + x - 8)

x \to 0 + lim (\frac{1 - e ^{x}}{x})

x \to 0 lim (\frac{x - 4}{x - 1})

x \to - 4 lim (5 x^{2} - 9 x - 8)

x \to 0 lim (\frac{1}{4} x^{2})

What is the limit as n approaches infinity of e^0 ?
The limit as n approaches infinity of e^0 is 1