What is the limit as x approaches-2+of sqrt(4-x^2) ?

The limit as x approaches-2+of sqrt(4-x^2) is 0

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limit as x approaches-2+of sqrt(4-x^2)

x \to - 2 + lim (4 - x^{2})

0

Solution steps

x \to - 2 + lim (4 - x^{2})

Plug in the value

x = - 2

= 4 - (- 2)^{2}

Simplify

4 - (- 2)^{2} : 0

= 0

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What is the limit as x approaches-2+of sqrt(4-x^2) ?
The limit as x approaches-2+of sqrt(4-x^2) is 0