What is the limit as x approaches 0 of x^{pix} ?

The limit as x approaches 0 of x^{pix} is Does not exist

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of x^{pix}

x \to 0 lim (x^{π x})

Does not exist

Solution steps

x \to 0 lim (x^{π x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x^{π x}) = 1

x \to 0 - lim (x^{π x}) =

Does not exist

= Does not exist

x \to \infty lim (x 6^{x} + 7^{x} + 8^{x})

x \to 1 lim (x^{2} - 17)

t \to 0 lim (\frac{e ^{5 t} - 1}{sin ( t )})

x \to \infty lim (12 x^{3})

x \to 0 lim ((1 + \frac{4}{x ^{5}})^{x})

What is the limit as x approaches 0 of x^{pix} ?
The limit as x approaches 0 of x^{pix} is Does not exist