What is (\partial)/(\partial x)(9(xyz)/(x+y+z)) ?

The answer to (\partial)/(\partial x)(9(xyz)/(x+y+z)) is (9yz(y+z))/((x+y+z)^2)

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(\partial)/(\partial x)(9(xyz)/(x+y+z))

\frac{\partial}{\partial x} (9 \frac{x yz}{x + y + z})

\frac{9 yz ( y + z )}{( x + y + z ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (9 \cdot \frac{x yz}{x + y + z})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 yz \frac{\partial}{\partial x} (\frac{x}{x + y + z})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 9 yz \frac{\frac{\partial}{\partial x} ( x ) ( x + y + z ) - \frac{\partial}{\partial x} ( x + y + z ) x}{( x + y + z ) ^{2}}

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x + y + z) = 1

= 9 yz \frac{1 \cdot ( x + y + z ) - 1 \cdot x}{( x + y + z ) ^{2}}

Simplify

9 yz \frac{1 \cdot ( x + y + z ) - 1 \cdot x}{( x + y + z ) ^{2}} : \frac{9 yz ( y + z )}{( x + y + z ) ^{2}}

= \frac{9 yz ( y + z )}{( x + y + z ) ^{2}}

\int \frac{3}{x + 3} d x

x^{c o s (x)}

\int \frac{2}{sin ( 2 x )} d x

\frac{d}{d x} (5^{- 2 x})

\frac{d ^{2}}{d x ^{2}} (\frac{e ^{x}}{cos ( x )})

What is (\partial)/(\partial x)(9(xyz)/(x+y+z)) ?
The answer to (\partial)/(\partial x)(9(xyz)/(x+y+z)) is (9yz(y+z))/((x+y+z)^2)