What is the limit as x approaches 1 of e^{-1/(x-1)} ?

The limit as x approaches 1 of e^{-1/(x-1)} is diverges

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limit as x approaches 1 of e^{-1/(x-1)}

x \to 1 lim (e^{- \frac{1}{x - 1}})

diverges

Solution steps

x \to 1 lim (e^{- \frac{1}{x - 1}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (e^{- \frac{1}{x - 1}}) = 0

x \to 1 - lim (e^{- \frac{1}{x - 1}}) = \infty

= diverges

h \to 0 lim (\frac{ln ( 1 + h ) - 0}{h})

x \to 0 lim (5 x^{2} + 4 x + 8)

x \to \infty lim (\frac{10 x ^{3} - 7 x + 2}{2 x ^{2} + 9 x + 6 x ^{3}})

x \to 1 lim (x^{\frac{1}{x}})

x \to 0 lim (- \frac{2}{x ^{4}})

What is the limit as x approaches 1 of e^{-1/(x-1)} ?
The limit as x approaches 1 of e^{-1/(x-1)} is diverges