What is the solution for y^'-3y=-6y^3 ?

The solution for y^'-3y=-6y^3 is y=sqrt(1/(-e^{-6t-c_{1))+2}},y=-sqrt(1/(-e^{-6t-c_{1))+2}}

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y^'-3y=-6y^3

y^{^{'}} - 3 y = - 6 y^{3}

y = \frac{1}{- e ^{- 6 t - c_{1}} + 2}, y = - \frac{1}{- e ^{- 6 t - c_{1}} + 2}

Solution steps

y^{'} (t) - 3 y = - 6 y^{3}

Solve Bernoulli ODE:

y = \frac{1}{- e ^{- 6 t - c_{1}} + 2}, y = - \frac{1}{- e ^{- 6 t - c_{1}} + 2}

y = \frac{1}{- e ^{- 6 t - c_{1}} + 2}, y = - \frac{1}{- e ^{- 6 t - c_{1}} + 2}

\int_{0}^{1} \frac{4}{1 - x ^{2}} d x

x \to 0 lim (\frac{x}{x ^{2} - 9 x})

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} + e ^{- x}})

x^{2} y^{^{'}} + 2 x y = ln (x), y (1) = 3

x, 7, \frac{x ^{2}}{28}

What is the solution for y^'-3y=-6y^3 ?
The solution for y^'-3y=-6y^3 is y=sqrt(1/(-e^{-6t-c_{1))+2}},y=-sqrt(1/(-e^{-6t-c_{1))+2}}