What is the derivative of cos(2x-2sin(x)) ?

The derivative of cos(2x-2sin(x)) is -sin(2x)*2-2cos(x)

What is the first derivative of cos(2x-2sin(x)) ?

The first derivative of cos(2x-2sin(x)) is -sin(2x)*2-2cos(x)

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\frac{d}{d x} (cos (2 x) - 2 sin (x))

- sin (2 x) \cdot 2 - 2 cos (x)

Solution steps

\frac{d}{d x} (cos (2 x) - 2 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cos (2 x)) - \frac{d}{d x} (2 sin (x))

\frac{d}{d x} (cos (2 x)) = - sin (2 x) \cdot 2

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

= - sin (2 x) \cdot 2 - 2 cos (x)

\int_{2}^{3} \int_{2}^{6} (x y e^{x + y}) d y d x

f (x) = \frac{x - 3}{2}

2 x y y^{^{'}} = x^{2} - y^{2}

x \to 0 lim (csc (6 x))

y^{^{'}} = 0.5 y - 450

What is the derivative of cos(2x-2sin(x)) ?
The derivative of cos(2x-2sin(x)) is -sin(2x)*2-2cos(x)
What is the first derivative of cos(2x-2sin(x)) ?
The first derivative of cos(2x-2sin(x)) is -sin(2x)*2-2cos(x)