What is the derivative of 3x^2-2y^2 ?

The derivative of 3x^2-2y^2 is 6x-4y(dy)/(dx)

What is the first derivative of 3x^2-2y^2 ?

The first derivative of 3x^2-2y^2 is 6x-4y(dy)/(dx)

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\frac{d}{d x} (3 x^{2} - 2 y^{2})

6 x - 4 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (3 x^{2} - 2 y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 y^{2})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 y^{2}) = 4 y \frac{d y}{d x}

= 6 x - 4 y \frac{d y}{d x}

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What is the derivative of 3x^2-2y^2 ?
The derivative of 3x^2-2y^2 is 6x-4y(dy)/(dx)
What is the first derivative of 3x^2-2y^2 ?
The first derivative of 3x^2-2y^2 is 6x-4y(dy)/(dx)